Schoolwork Help! Braniacs needed!

[TNC9852002]

Ok, someone help me solve this problem:

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A hockey player is standing on his skates on a frozen pond when another player is moving with a puck at a uniform speed of 12 m/s. After 3 seconds, the first player makes up his mind to catch up. If he accelerates at 4 m/s^2, how far will he have to skate before catching up with the second player?

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-TNC

 

[Erzengel]

300,000,000 meters/second divided by 186,000 miles/second = 1,612.9 meters/mile

Also, stop with the video games and sit down and read the chapter for a change.

 

[triplefive]

186,000x/s = 3 x 10^8y/s, where x = miles and y=meters

x = (3 x 10^8/186,000) y, and the seconds cancel out because you're dividing 1/s by 1/s, which of course equals 1.

 

[TNC9852002]

Wrong question. Updated.

-TNC

 

[Erzengel]

Now I just think you are trying to get people to do your homework for you.

 

[Kmack]

Now I just think you are trying to get people to do your homework for you.

LMAO! Sorry TNC, I suck at math

 

[TrailerCues]

 

[GoldenAgeHero]

damn i forgot the equation to this problem. it has something to with x= initial velocity plus something times time plus gravity over 2 with time as an exponent.......x=V_0+(something)t+((9.81+accel)/2)^t. look in your book for a similar equation. i could be wrong tho. but i feel like im close.

 

[jaguarr]

Do your own homework.

jag

 

[triplefive]

edit, nevermind, ignore what i said

 

[amazingfantasy15]

That terminator video was really funny, although it's completely off topic.

 

[GoldenAgeHero]

to triplefive: yeah it does......not saying that im right but im pretty sure it does. anyone can prove me wrong?

 

[triplefive]

to triplefive: yeah it does......not saying that im right but im pretty sure it does. anyone can prove me wrong?

yeah you're right

it's been like 6 years since i've done this kind of math

 

[TNC9852002]

Now I just think you are trying to get people to do your homework for you.

No. I don't have to solve this problem. I'm stumped at attempting to solve it and I was just being friendly to ask if anyone could provide some help.

Do your own homework.

jag

It's not technically "homework".

-TNC

 

[Holly Goodhead]

I paid this polish girl to do my math homework. A+! Her name was Olivia but pronunced it Ulva.

 

[webhead731]

Ok, someone help me solve this problem:

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A hockey player is standing on his skates on a frozen pond when another player is moving with a puck at a uniform speed of 12 m/s. After 3 seconds, the first player makes up his mind to catch up. If he accelerates at 4 m/s^2, how far will he have to skate before catching up with the second player?

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-TNC

You better figure it out and get it right! You might have to use that in five years!

 

[webhead731]

OMGROTFLOL!

 

[GoldenAgeHero]

I paid this polish girl to do my math homework. A+! Her name was Olivia but pronunced it Ulva.

stop getting jokes from seinfeld

 

[triplefive]

x = position of first skater = 12t
y = position of second skater = 0.5(4)t^s
[position of y = intial position + initial velocity * time + 1/2 acceleration x time squared] one of the kinetic motion equations

so, set x = y and solve

 

[Holly Goodhead]

stop getting jokes from seinfeld

That's from Seinfeld?

 

[Spider-Man Luvr28]

Wooow. You all are so smart. Maybe I should start posting my math problems on here.

 

[Kmack]

Wooow. You all are so smart. Maybe I should start posting my math problems on here.

I've considered it

 

[GoldenAgeHero]

x = position of first skater = 12t
y = position of second skater = 0.5(4)t^s
[position of y = intial position + initial velocity * time + 1/2 acceleration x time squared] one of the kinetic motion equations

so, set x = y and solve

yup you found the equation. haha i was off. but i said was close.

 

[GunBlade]

**** you. Do your own damn homework.

 

[TNC9852002]

x = position of first skater = 12t
y = position of second skater = 0.5(4)t^s
[position of y = intial position + initial velocity * time + 1/2 acceleration x time squared] one of the kinetic motion equations

so, set x = y and solve

The difficulty that I'm having with this problem is figuring out the stationary hockey player's position before he decides to catch up.

You also haven't taken into account that the first player doesn't accelerate until after 3 seconds.

-TNC