~The BrAiN tEaSeR Thread~

[Spider-Fan]

This is what I would call an eduacted guess but my answer is 7.

Basically, the first person is going to call out what is the majority color of the hats. There will have to be a majority because there are 9 hats he will see. He may surely. The next person takes one from the majority and says the majority number unless the number is now even. If he says white, he may die , but all the others know exactly how many red and whites there were and therefore can figure out what colour hat they had from knowing if the person behind is alive or dead and the colours ahead.

However, if there are still more reds, the combo can only be either 8 reds; 7 reds, 1 white; 6 reds; 2 white; 5 reds, 3 whites (not including what the 9th person is wearing).

Obviously the worse case scenario is the 6 and 2. The person will say red as that is the majority ahead, if he dies then the person ahead knows one of the whites is gone and that he will see only 1 white ahead. Therefore all the others are likely to say red, meaning only one more will die.

Nope

Man, people are having a hard time with this one.

 

[Ahura Mazda]

Nope

Man, people are having a hard time with this one.

Then is it 8 because I was fiddling with that because I know you can save at least 7 and I don't see how you can save 9.

 

[Kaboom]

just in case you all are wondering, any riddle involving math i automatically skip.

 

[Spider-Fan]

Then is it 8 because I was fiddling with that because I know you can save at least 7 and I don't see how you can save 9.

What would be your method? I can't tell you if the number is correct or not...you need a number and method.

 

[Ahura Mazda]

Actually using the methodology stated above you can only be sure to save 6. I made a mistake stating 7.

 

[Spider-Fan]

Actually using the methodology stated above you can only be sure to save 6. I made a mistake stating 7.

Oh, well in that case, it is still wrong t:

 

[November Rain]

Nope

Man, people are having a hard time with this one.

it's working with colours and numbers at the same time. It's just not commonly done but it's crazy obvious once you know the first step

 

[Spider-Fan]

it's working with colours and numbers at the same time. It's just not commonly done but it's crazy obvious once you know the first step

Exactly. I got this one. You just need to get the right steps.

 

[Spider-Fan]

just in case you all are wondering, any riddle involving math i automatically skip.

That makes me

 

[Ahura Mazda]

Oh, well in that case, it is still wrong t:

Wrong again I was right, it was 7 using my method. damn trying to get to 8 makes me question everything and I am guessing I have to come up with a ew way.

 

[wiegeabo]

Answer #35:

There's a 50% chance the first gnome will be the only one to die, and a 50% chance all the gnomes will live. (Or, putting it another way, the first gnome has a 50-50 shot of dying, all the other gnomes will live.)

The first gnome counts all the white hats he an see and says white if there are an odd number, red if there are an even number. There's a 50% chance his hat won't match the color he says, so he's got a 50-50 shot of dying.

The second gnome counts the number of white hats. If he sees an even number, his hat must be white because he sees one less white hat. If he sees an odd number, his hat must be red.

If second next gnome says white, that tells the others that there are now an even number of white hats. So the third counts white hat, if he sees an even number he knows his hat is red. An odd number tells him his hat is white because there's one less white hat. And when he says his hat is white, it tells the other gnomes to there are an odd number of white hats.

And that's how it goes down the line. Anytime a gnome says white, the remaining gnomes know to switch from looking for evens to odds, or odds to evens.

 

[Ahura Mazda]

Answer #35:

There's a 50% chance the first gnome will be the only one to die, and a 50% chance all the gnomes will live. (Or, putting it another way, the first gnome has a 50-50 shot of dying, all the other gnomes will live.)

The first gnome counts all the white hats he an see and says white if there are an odd number, red if there are an even number. There's a 50% chance his hat won't match the color he says, so he's got a 50-50 shot of dying.

The second gnome counts the number of white hats. If he sees an even number, his hat must be white because he sees one less white hat. If he sees an odd number, his hat must be red.

If second next gnome says white, that tells the others that there are now an even number of white hats. So the third counts white hat, if he sees an even number he knows his hat is red. An odd number tells him his hat is white because there's one less white hat. And when he says his hat is white, it tells the other gnomes to there are an odd number of white hats.

And that's how it goes down the line. Anytime a gnome says white, the remaining gnomes know to switch from looking for evens to odds, or odds to evens.

That works, damn I went around it, hit it from different angles, checked all the borders, skirted the answer and never actually got it like you did.

 

[wiegeabo]

Well, I'll admit I looked at the answer and thought the answer they gave didn't work. Then I realized they just got lazy and didn't explain what happens after the fist two gnomes, so it took me a while to figure out the real method.

 

[Spider-Fan]

Answer #35:

There's a 50% chance the first gnome will be the only one to die, and a 50% chance all the gnomes will live. (Or, putting it another way, the first gnome has a 50-50 shot of dying, all the other gnomes will live.)

The first gnome counts all the white hats he an see and says white if there are an odd number, red if there are an even number. There's a 50% chance his hat won't match the color he says, so he's got a 50-50 shot of dying.

The second gnome counts the number of white hats. If he sees an even number, his hat must be white because he sees one less white hat. If he sees an odd number, his hat must be red.

If second next gnome says white, that tells the others that there are now an even number of white hats. So the third counts white hat, if he sees an even number he knows his hat is red. An odd number tells him his hat is white because there's one less white hat. And when he says his hat is white, it tells the other gnomes to there are an odd number of white hats.

And that's how it goes down the line. Anytime a gnome says white, the remaining gnomes know to switch from looking for evens to odds, or odds to evens.

Correct sir...that is it

 

[Spider-Fan]

Now we need a new one

 

[wiegeabo]

We need a new two, don't we?

 

[wiegeabo]

Riddle #36:

Two men on opposite sides of the same boat look out at the horizon. One looks due East, the other due West. And, yet, they can still see each other. How?

 

[Spider-Fan]

They are facing opposite directions

 

[November Rain]

yah, they are looking inwards not outwards

 

[wiegeabo]

Right. I figured we needed one that would be easy to answer.

 

[November Rain]

I won't be here in 24 hours to reveal the answer to anything i put up so just go on ahead without me.

 

[wiegeabo]

Riddle #37:

A train leaves New York for Boston. Five minutes later another train leaves Boston for New York, at double the speed. Which train will be closer to New York when they encounter?

 

[Spider-Fan]

I know this, but I forgot how to explain it

 

[Carcharodon]

They'll be an equal distance from New York, since they're encountering one another.

 

[wiegeabo]

They'll be an equal distance from New York, since they're encountering one another.

Right.